What is the probability of getting a 4 and 3, in any order, when two six-sided die are rolled together?
how do we arrive at answer as 1/18 i am not able to understand the explanation. Please help
2 \cdot P(X = 4) \cdot P(X = 3) = 2 \cdot \frac{1}{36} = \frac{1}{18}
why is it multiplied by 2 and not 1/36 * 1/36
Case 1:
The probability of getting a 4 on the first die then a 3 on the second is: \frac 16 \cdot \frac 16 = \frac {1}{36}
Case 2:
Similarly, the probability of getting a 3 on the first die then a 4 on the second is:
\frac 16 \cdot \frac 16 = \frac {1}{36}
Your questions wants either case 1 or case 2, so:
\frac{1}{36} + \frac{1}{36} = 2 \cdot \frac{1}{36} = \frac{1}{18}
okay understood now thanks