Area of two triangles

Hi guys, I know it gives the same result but I just want to check if my logic is right. In this example the area of two triangles is calculated and then added. But what I thought was the following (quick summary).

If by drawing the perpendicular line we can define the length of the largest triangle (the combination of triangle I and II) as 2 + 2 square root of 3, the we can use that as the base of the triangle. Correct?
Then because of other calculations we can define the length of the perpendicular line as 2, which we can use as the height of the triangle. Correct? Imagine the triangle as lying down on the hypothenuse of the combined triangle.
Then we can use the standard formula for area of triangle such as

base x height x 1/2
2 + 2 square root of 3 x 2 x 1/2
2 + 2 square root of 3 x 1
= 2 + 2 square root of 3

So I just want to know if the taking the described calculated figures can be used as the height and base of the largest triangle.

Thanks!

Yes.

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