Hi,
May I ask for some help regarding? I understand why A would be correct if they had the same lengths. But I am wondering how i can prove it is greater than B with different lengths/perimter.
Thanks
Hi, use the fact:
For a rectangle with a fixed perimeter, the square has the largest area.
Hi there,
Thank you for your help. This is understood.
However as they have different perimiters, I am struggling to prove beyond doubt that B is smaller. Is there any sure way?
Kind regards,
Hosni
What is the maximum value quantity B can take? This should be in reference to what i mentioned earlier.
As a further hint, a square can be split into 2 isosceles right triangles.