It doesn’t say positive integers. So can’t we take -1, 0, 1 as three consecutive integers? And then the product will be 0.
0 is a multiple of every integer. So, every integer must divide 0 except 0 (the divisibility of 0 is undefined).
0 is a multiple of every integer. So, every integer must divide 0 except 0 (the divisibility of 0 is undefined).
“always”
You just gave me a “special” case
Ohh! Yes. Got it. Thanks