Arithmetic Foundation Quiz #2 | Question-6


It doesn’t say positive integers. So can’t we take -1, 0, 1 as three consecutive integers? And then the product will be 0.

0 is a multiple of every integer. So, every integer must divide 0 except 0 (the divisibility of 0 is undefined).

“always”

You just gave me a “special” case

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Ohh! Yes. Got it. Thanks