Let the secant line intersect the circle at two points: A and B. In that case, \triangle APB is an isosceles triangle, so it should be obvious now that \angle x < 90^{\circ} bc otherwise the central angle would be \leq 0.
This question isn’t related because this is just a special case of inscribed angle theorem. Owing to that, you get that \angle C = 90^{\circ}.
Thanks/ i do understand these are not related diagrams. it’s just that i find it really confusing…as they look similar to someone like me whose Quant skills are dismal