Are y-intercept and minimum y value 2 different concepts? Because here the minimum value of y must be -2 if x=-2. But according to the solutions y = 2?
Hi there. The way you get minimum value and y intercept are different. So for y-intercept, you set x=0 to get the y value. For minimum value, you can do the vertex formula which is -b/2a , which gives you x and then you plug that into the equation to get the y for (x,y) that represents minimum value. Let’s say for example y=x^2-4x + 3, y intercept is x=0 –> y=3 at point (0,3). Now let’s do minimum value: -b/2a = 4/(2)(1) =2, plug in 2 into the original equation to get y= -1 as the minimum y value
Got it thanks!
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