A list of 10 unique words is randomized twice. Both times, the
10 words are written down from left to right. What is the probability that none of the first three words in the first randomized trial match the first three words in the second randomized trial?
My approach
Find the probabaility the three words remain together.
That would be , A = 1 x 7! / 10!
They don’t remain together = 1- A
Shouldn’t I get the same answer . What am I missing please help