The answer is option C irrespective of the events being independent or mutually exclusive.
But I didn’t understand how it could be the same for mutually exclusive events.
For mutually exclusive events, we don’t have too subtract the ‘AND’ case right, because its value is 0?
The events cannot be mutually exclusive because that would imply that there is no chance for both Salim and Latika to pass their tests, which is not stated anywhere. They are independent however.
I don’t get it
P(Salim) + P(Latika) = 1 should be true? Is that what you’re implying?
For example, the probability of me getting a 335 in GRE and the probability of person X getting a 335 are mutually exclusive right?
This is correct
No, that is not what I am implying.
Can you explain pls? I’m unable to comprehend why mutually exclusive is not possible
See above.
these are not mutual exclusive, they are independent events
right
Can you confirm the answer is C? I think it should be D
Quantity B is actually computing P(A \cup B) (for either of the 2 independent events happens); however, P(both) should be P(A \cap B)=P(A)P(B), which is why I 'm saying the answer is D
Yes, how do you know that? Why can’t it be mutually exclusive?
Yep it is! It’s from Greg’s difficult quant practice series
It’s asking for case 1 OR case 2 OR BOTH cases! So the answer is correct
Because mutual exclusive means if event A happens, event B cannot happen at the same time. In this case, the probability of event A occurs doesn’t affect P(B).
oh, okay, so it is or, which means it is not imperative. Is this what you mean?
Ahhhhh gotchu. Thanks!!
Yes and no. OR means that we have to calculate the probability of ANY of the 3 cases
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