Hi!
Had a doubt from the pattern recognition video:
Context: Here, Greg explain up till choosing b=4, where I understand that the final value is increasing till b=3,then becomes equal to an earlier case in b=4. It is there that he concluded the answer is b=3.
But my question is: How can I say b=3 confidently without even assessing later cases. where as per the pattern, a value should be rising, and then becoming equal to an earlier case? How will I know if b=3 is the max. point?
Would be super if you can help me with this, thanks!
Try graphing using Desmos or similar.
Thanks! Checked, very interesting, it is declining.
Wanted to still confirm with you- without the aid of these in the exam, how do I know to stop at b^3- should I just stop knowing that I cannot calculate any further using only the GRE calculator?
You need to show that 2^{1/2} = 4^{1/4} and that, for example, 4^{1/4} > 5^{1/5} or 5^{1/5} > 6^{1/6} to establish the pattern. This can be done using only GRE tools.
Sorry I’m still having trouble determining how l can use only GRE calculator to for sure say 4^1/4 > 5^1/5?
I tried proving 5^1/4 - which I can calculate- but that is coming to be greater than 4^1/4. Maybe I’m missing something basic here, but not understanding how I proceed further to calculate 5^1/5
Square both sides to the power of 20.
