the answer given is A i.e. X is greater however if we put X as 4 it would still round off to 12.16 right?
in manhattan they have considered that we can roundoff to higher digit if the no. is greater than or equal to 5.
so , to make it 12.16 ; x should be >=5. is right
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The question asks about rounding the number to the nearest hundredth. It is math convention that 5, 6, 7, 8, 9 round up while digits 0, 1, 2, 3, 4 leave the number unchanged. Thus, in this example since 12.15x9 rounded to the nearest hundredth gives you 12.16, then x must be 5 or 6 or 7 or 8 or 9.
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but wouldn’t the 9 play a part?
For example, if X = 4 then 9 would change X i.e. 4 to 5. Therefore rounding off the hundredth place would still lead to 12.16 with X >= 4?
I think you would profit from reviewing the concept and how rounding works.
Yep had the concept wrong. Thanks! 
can’t 12.1549 be rounded to 12.16?
No. Check out the videos above to review the concept.