.5 C Is the answer (Jesus, I hate this character limit!!)

Putin, Can you please explain.

In order to satisfy the restriction which s/k is an integer, apparently, k has to be any odd numbers between[1,100]. Thus, P=50/100â€”>C

If I am correct. Draw a table : First Column K , Second Column S and Third Column S/K .

K | S | S/K | Part of Seq. |
---|---|---|---|

1 | 1 | 1 | Y |

2 | 3 | 1.5 | N |

3 | 6 | 2 | Y |

4 | 10 | 2.5 | N |

5 | 15 | 3 | Y |

6 | 21 | 3.5 | N |

7 | 28 | 4 | Y |

8 | 36 | 4.5 | N |

9 | 45 | 5 | Y |

10 | 55 | 5.5 | N |

So from this pattern we observe that half of the values out of 10 are part of the sequence . Hence, we reach to a conclusion from this pattern that for half the values of K (K is from 1 to 100 so for 50 values) the S/K will be part of the sequence.

2 Likes

Damnâ€¦nice!

Mr. Putin, your third columnâ€“the value of s/k, seems not right. Yes, it is correct now

Thank You so much for correction !!

1 Like