Why is the answer not 5? It’s part of the Pythagoras triplets?

What if the hypotenuse is 4?

But it’s a right triangle? If we solve it using Pythagorus, it will yield 5? unless we are saying

3 + 4 > x → x < 7

3 + x > 4 → x > 1

Since 1 < x < 7, we cannot ascertain the 3rd side? Is that the reason? But if it is, I am still puzzled why we can’t use pythagorus to solve this problem.

Consider the right triangle whose height is 3 and hypotenuse is 4. Does that satisfy the constraints of the problem? What is its area?