How do we approach this question? Are we eyeballing the area in this question?

In figure and figure 2 as u can see, there are 2 right-angle triangles, solve for the hypotenuse and find the area

A quicker way to solve is in figure one consist of 2 symmetrical triangles and let the hypotenuse be a and b so the total area is (1/2)*a*b but since the figure is symmetrical the are is 2*(1/2)*a*b = a*b

In figure 2 the hypotenuse is the same a and b and the area is a*b

so I guess the answer is C

Cool. Thanks!