Gregmat Practice test 1 q11

Is this method correct ?

Area of circle= pi*r^2 r=1, so area=pi

Area of rectangle= 24
ow many circles can be in this rectangle= 24/pi or 24/3.14=7.6433121 approx 8

So probability that circle is entirely contained = 8/24= 1/3

I solved through this method, want to verify this once

While crude and technically incorrect, I like what you’ve done. What you’re doing is basically finding the number of circles in the rectangle. While that approach has mathematical errors (because you can’t “fit” circles exactly in a rectangle), as an approximation it’s OK enough in this case.

Formally, your answer will always be \frac{1}{\pi r^2}, while the correct answer for a circle with radius r and rectangle dimensions p and q respectively is

\frac{(p - 2r)(q - 2r)}{pq}

which is clearly different.