Given, Perimeter of ABCD = 60.

So essentially , each side of square ABCD = 15

Give SRC = 60° , we know C=90°

SCR = 30° (30-60-90 Triangle)

Sides will be in the ratio of x : √3x : 2x

So , CS = √3x , SD = x , SR = 2x

(CS + SD = CD)

We know CD = 15,

√3x + x = 15 ---- eq’n-(1)

Perimeter of PQRS = SP + PQ + QR + RS = (4 * 2x) = 8x

From eq’n 1 , we know x = 15 / (√3+1)

Therefore Perimeter = 8 * ( 15 / (√3+1) )= 43.92

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