I guess there is a typo It should be peach candies.
Also the answer seems to be wrong
Jack is trying to find apple flavored candy
He puts candy back in the jar if it isn’t apple-flavored
So the probability should be 5/10 which means 0.5 > 0.4
Even if it’s the first or the third or the fourth attempt the probability should be 5/10
We’ll fix the “shirts” typo. Your explanation for the other problem isn’t right, but the question itself was faulty, which we’ve fixed.
I wanted to follow up on this since the question text has been changed so instead of creating a new thread I thought its better to ask it here. I want to confirm if my approach is correct or not.
Since we have to make sure Jack draws twice and that the second candy Jack draws is peach-flavored so there can be two possibilities. In one case, if the first candy is peach flavored and second candy is also peach flavored. The second case, when first candy is not peach flavored but second candy has to be peach flavored.
Solution- 2/10 * 1/9 + 8/10*2/10
2/10 * 1/9 - This captures the situation that both the candies are peach flavored and he is not replacing it in the bag
8/10*2/10 - This captures the that first candy is either orange or apple (total 8) and second one is peach but he is not replacing it so 2/10
This gives the answer- 2/10 * 1/9 + 8/10*2/10 = 0.182
So, B is greater than A
Is that the right approach ? @Leaderboard
This can’t work because the question says that he draws another candy only if the first one is not peach-flavoured.
Yeah right. So, that means first candy has to be either orange or apple and second has to be peach because only with this situation he will draw twice so the solution would be 8/10*2/10 = 0.16
Am I right?
That should work.
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Thanks!!