I’d say apart from option C, all of the rest are correct.
how do you solve? do you assume values of x & y?
I am wrting down my thought of process on paper. Please give me 3 min.
Hopefully this helps 
From the statement we can infer that y is positive
x and z are either both negative or both positive
So, we have two cases and because the question says “could” be true, we need to find only one example where this works:
i. x,y,z = 2,1,4
0 < 1 < 2 < 4
Also, 2 < 3 < 4
ii. x,y,z = 1,2,5
0<1<2<5
Also, 1 < 4 < 5
iv. x,y,z = 3,1.4,4
0<2.9<3<4
Also, 3 < 3.4 < 4
v. x,y,z = -1,2,-5
-3<-1<0<2
Also, 1<4<5
Now, c is not possible because if x and z are less than 0
and |x| < |z| then x<z can never be possible
|x| < |z| leads to x z when x and z are negative
this process will take more time
this is quick process, why you take 0<y<2?
For producing shorter segment lol. You can try the case where y>2 yourself.
Thanks
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