I’d say apart from option C, all of the rest are correct.

how do you solve? do you assume values of x & y?

I am wrting down my thought of process on paper. Please give me 3 min.

Hopefully this helps

From the statement we can infer that y is positive

x and z are either both negative or both positive

So, we have two cases and because the question says “could” be true, we need to find only one example where this works:

i. x,y,z = 2,1,4

0 < 1 < 2 < 4

Also, 2 < 3 < 4

ii. x,y,z = 1,2,5

0<1<2<5

Also, 1 < 4 < 5

iv. x,y,z = 3,1.4,4

0<2.9<3<4

Also, 3 < 3.4 < 4

v. x,y,z = -1,2,-5

-3<-1<0<2

Also, 1<4<5

Now, c is not possible because if x and z are less than 0

and |x| < |z| then x<z can never be possible

|x| < |z| leads to x z when x and z are negative

this process will take more time

this is quick process, why you take 0<y<2?

For producing shorter segment lol. You can try the case where y>2 yourself.

Thanks

Welcome.