Hey !
I have a query related to this.
To be mean=median, there are only two conditions. One is evenly spaced set and other is symmetrical set, but when you put x=13, it doesn’t satisfy both the conditions to prove mean=median.
How could x=13 fit over in this scene just by multiplying and subtracting with the numbers if it doesn’t follow the rules?
Any placement of 13 in this question can’t satisfy the two conditions of mean=median. Could you please explain about it.
If 13 is added into the set, the new median automatically becomes 25
Next we need to confirm if the new mean is also equal to 25, if so the mean = median, and 13 satisfied the requirements
To figure this out
We just need to; add all the elements of the new set together / divided by the new number of elements
(13+17+25+31+39)/5 = 125/5 = 25
This satisfies the second requirement
Hence when 13 is added to the set, the mean = the median
