Official Guide Practice Test 1 Section 6 Q8

[user8352]

The answer to this question is B.

But if you can bring the equation in the form of x^2 - 1 = 0 from there on → x can equal 1 or -1, so answer should be D.

Another way of approaching the problem is taking the negative sign out of the numerator on the LHS there by making it -(x-1)/(x-1) = 1/x → On solving it further you get the answer -1. Which supports answer B.

Not sure what the problem really is with the first method. Can someone please explain?

[Leaderboard]

Try putting x = 1 back in the original equation.

[user8352]

Got it, thanks! x=1 is not a solution since the denominator becomes 0.