Hello All

I didnâ€™t quite understand the below problem. Can someone explain it?

Thanks!

Let us consider 3 points P,Q,R and the line segments PQ, QR, and RP.

Now the points that are equidistant from P and Q are the points on the line - the perpendicular bisector - of line segment PQ. Letâ€™s call that perpendicular bisector as line L1. Similarly you can find other 2 lines L2 and L3.

So you want the points which are equidistant from all 3 points and not just 2 of them. So itâ€™s basically the intersection of the lines L1, L2 and L3.

L1, L2 and L3 intersect at a single point which is the center of a circle which passes through all P,Q and Ra

The question simply states that PQR is a triangle. so there is only one point which is equidistant from P and Q and R which is the centroid of the triangle. hence answer shall be B.