OG Practise Test 2 Quant 1 Q 23

GRE Quant Problem Solving
1

Hello All :slight_smile:

I didn’t quite understand the below problem. Can someone explain it?

Thanks!

Q.23
Q.232660Ă—848 73.9 KB

2

Let us consider 3 points P,Q,R and the line segments PQ, QR, and RP.

Now the points that are equidistant from P and Q are the points on the line - the perpendicular bisector - of line segment PQ. Let’s call that perpendicular bisector as line L1. Similarly you can find other 2 lines L2 and L3.

So you want the points which are equidistant from all 3 points and not just 2 of them. So it’s basically the intersection of the lines L1, L2 and L3.

L1, L2 and L3 intersect at a single point which is the center of a circle which passes through all P,Q and Ra

3

The question simply states that PQR is a triangle. so there is only one point which is equidistant from P and Q and R which is the centroid of the triangle. hence answer shall be B.