I do get that c is distinctively visible to the rightward of a and hence c>a but can we ascertain that d>b in such close cases?
Yea, I think we can make a deduction by looking at the graph that (c,d) has a higher x and y value when compared to (a,b). Also, even if b and d were the same y-value, c > a which makes quantity A greater.
Thanks, So if there is no demarkation in x and y axis , can we still confidently assume that about the points just by seeing? And I know for sure that this sort of assumption is not applicable in geometry.
In the solution it did say about peculiar case of coord- geometry but, can we extrapolate this logic to the graphs without demarkation? Because in ETS wherever it happened, they have marked points and separation in x and y axis like this.
For coordinate geometry problems, yes, as they are to scale.