Why can’t we work with angles here? We know that BD is perpendicular, which turns these two triangles into two 45-45-90 triangles, no?
Do it as b is 90° so according to Pythagoras the side bc is also 8 hence both angle a nd c are 45 in triangle ABD a is 45 d is 90 so a is also 45 hence now use 45 45 90 triangle and then bd become 8 /root 2
So 8/8✓2 it makes ✓2 and value of ab/bd is 1.43 and 4/3 is less than 1.43 so A is correct
Nope, \overline{BD} is not an angle bisector. Just because there’s a right angle at D doesn’t imply anything about \overline{BD} being a perpendicular bisector or an angle bisector.
Got it! Thank you!