3.625 = 3 + \frac{625}{1000} = 3 + \frac 58. In this case, the remainder would be 5.
However, we could rewrite this as:
3 + \frac{5n}{8n} for n in \mathbb{Z} hence any multiple of 5 would work.
I think that’s what the question is going for.
3.625 = 3 + \frac{625}{1000} = 3 + \frac 58. In this case, the remainder would be 5.
However, we could rewrite this as:
3 + \frac{5n}{8n} for n in \mathbb{Z} hence any multiple of 5 would work.
I think that’s what the question is going for.