Hi! This is question #14 from Level 2 quant foundation quiz. Why can’t the height for this problem be 10 (versus 8)? And thus the volume of the cylinder approximately equals 785, and 785 is roughly 82% of area of box? Why does the height have to be 8 in the solution?
If h = 10, r = 8. Is that more optimal?
Wait, sorry — I now understand why height cannot be 10. But why can it not be 12?
Area of box = 960
For cylinder, if…
Diameter = 10
Height = 12
…then volume of cylinder = π (5^2) (12) =942.478
Which is 98% of 960
Is it because that then means the width of the box is 8, which constricts the diameter (which would then need to be 8)?
That.