Hello, if the question says “could”, it could have 4 prime divisors since it would be a^1*b^1*c^1*d^1 \rightarrow 2^4 = 16? I understand that if a^2*b^1*c^1*d^1 = 24 and it couldn’t be, but there is one case in which it has 4 prime divisors.
Let’s say the number with 20 factors is x.
Here are different cases of what x could be, where a,b,c,and d are prime integers.
- x=a^{19} → 19+1 = 20
- x= a^4 \times b^3 → (4+1) \times (3+1) = 20
- x = a^1 \times b^1 \times c^4 → (1+1) \times (1+1) \times (4+1) = 20
Can we break it up in any other ways?