x and y are both integers If 4 ≤ x < 7 < y ≤ 12, then what`s the range of (x−y)^2?
Hey @iori.yagami
The value of the above expression will be maximum when value of x is smallest and y is biggest.
x=4, y=12, value from expression equals to -8^2 = 64.
Similarly, the value of the above expression will be minimum when value of x is biggest and y is smallest.
x=6, y=8, value from expression equals to -2^2 = 4.
Hence the range as per me should be difference from 64 to 4 for said expression i.e. 60.
I’m not sure what the official answer is, let me know if this helps.
Thanks
Jeet
It’s asking for the range of (x-y)^2
So, the answer would be 16 - 4 = 12
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My bad, thank you for flagging @vidishas99 
8 square = 64
Range will be = 64-4= 60
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Can’t seem to catch a break today @iori.yagami @vidishas99 ^^
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