x and y are both integers If 4 ≤ x < 7 < y ≤ 12, then what`s the range of (x−y)^2?

Hey @iori.yagami

The value of the above expression will be **maximum** when value of **x is smallest and y is biggest.**

**x=4, y=12,** value from expression equals to -8^2 = **64.**

Similarly, the value of the above expression will be **minimum** when value of x **is biggest and y is smallest.**

**x=6, y=8,** value from expression equals to -2^2 = **4.**

Hence the **range** as per me should be difference from 64 to 4 for said expression i.e. 60.

I’m not sure what the official answer is, let me know if this helps.

Thanks

Jeet

It’s asking for the range of (x-y)^2

So, the answer would be 16 - 4 = 12

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My bad, thank you for flagging @vidishas99

8 square = 64

Range will be = 64-4= 60

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Can’t seem to catch a break today @iori.yagami @vidishas99 ^^

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