Hey @gregmat, I believe that this statement needs to be modified a bit, because if we plug in a negative integer for x, the statement becomes false.
Correct - we’ve put a note on the video as a result.
Thank you! That would be helpful now!
Good call
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Hello everyone!
I’m a bit confused here in remainders part deux.
I get this what’s written as Note. But I had a confusion, what if we say both x and y are negative and integer. Can I factorize them?
(-x)/(-y) = x/y ??
As for 3/6 remainder is going to be 3, of the original fraction, you cannot factorize it as ½ and say the remainder is 1.
So, can we write the note as, considering x/y, where x and y are both POSITIVE & INTEGERS and y>x, the remainder is simply x?
x cannot be negative so no.