\angle CZX == \angle CXZ = 30 as they’re opposite to equal side! thus, \angle ZCX = 120 (all sides of a triangle add to 180!)and \angle YCX = 180-120 = 60 Now, if u drop a perpendicular from X on YC and name it G , you’ll have a 30-60-90 triangle. thus, sides will be in the ratio 1: \sqrt3: 2 You will get the height of triangle (triangle CXY)as \sqrt 3 Now, area of sector(sector is CYX) is \pi \times r^2 \times \frac{\theta}{360} here, \theta=60 and r=2 or ar. of sector is \frac{2}{3} \pi Now, if we subtract the area of triangle from it then we’ll have that segment area, area of triangle(CXY) = \sqrt3 So, \frac{2}{3} \times \pi - \sqrt3 = .36 Thus, ans is A