Two classes A and B have students in the ratio 15: 42.
Quantity A = The number of students from class B must be shifted to class A so that class A will have double the students than that in class B ?
Quantity B = 23
Two classes A and B have students in the ratio 15: 42.
Quantity A = The number of students from class B must be shifted to class A so that class A will have double the students than that in class B ?
Quantity B = 23
So… do you want help?
yes sir
I am very much confused between option C and option D
Okay, can you show how u got to C or D?
yes surely,
if the number of students shifting from class b to class a is let’s say “x” then the new ratio would be 2:1 according to question right.
so we can write
15+x/42-x = 2/1
and that would give the value of x
which would be 23
then, we can find to what factor the ratio increased
15y+23=2(42y-23) #as it is double
then it would result in 1
so we know that total number of students shifted is 23. So answer is C
but here is my question we can also do like 15y and 42y and still make a shift such that it ratio become double the class B in class A . sooo you know it can be 46 students …
so it is not possible to get answer without knowing what factor it is getting increased right
so answer could be D…
omg i just realised how terribly i have answered…
Yeah, i think you’ve solved it.
How i would do it is basically:
2 = \frac AB = \frac{5y + x}{14y - x} \implies \frac{23y}{3} = x
This means that integer solutions for x occur exactly when y = 3k, for k in \mathbb{N}. This goes on to imply that x can be any positive multiple of 23.
To address your actual question, you considered a specific value of y (namely y = 3 which occurs when k = 1) to land at answer C, but any positive integer you select for k would give valid values of y and thus x.
P.S. our variables mean the same thing, so as to cause less confusion to you
so answer is D?
Yes, for the reason I mentioned.
To restate, x can be any positive multiple of 23.
For example, if we suppose x = 46 (and thus consequently y = 6), then you could have something like:
\frac{30 + 46}{84 - 46} = 2, which works out well according to the constraints in the question
In case, you don’t get what those numbers mean then:
30 = number students in Class A
84 = number of students in class B
46 = number of shifted students
thanks a lot good sir :))