Hey everyone.
So in this question (H/W from 2-month study plan week 5 day 1) we had to solve it using the choosing numbers strategy. Greg solved it differently, and got the correct answer C, whereas my way of solving it led it to B. I don’t think there’s anything wrong with my way, is there something that I’m missing? Because I know that rounding up that number is dangerous, especially in a QC question. Thanks for your time!
(Greg’s way:
he extended the line FG to FC and cut the square in half.)
This bit is not the area of triangle A.
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Oh, may I ask why? The base is root(2)/2 and the height is 2. If you draw a line from D to E, you can draw a perpendicular line towards F, so you find that the height is 2.
Not sure I follow how you got height =2. You can solve for \overline{GF} through pythag and then you can have your true base/height.
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Ohhhhh, I totally got confused with the triangle being upside down, and I thought I could use this trick:
I also neglected the fact that since FG cuts BD in half, the 2 angles are also 90 degrees.
Thank you so so much!!!
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