What would be the area of the triangle with length 4?

Area of an equilateral triangle = half *half* \sqrt{3} = 4 root 3, if we have to double the size then multiply by 2, isn’t that right?

Area of Equilateral Triangle = (√3 / 4) × a²

Where a is the side length.

Here in this question,
a = 4

So initially, the area would be

A = (√3 / 4) × 4²

A = (√3 / 4) × 16

A = √3 × 4

We are looking to double the size (area), the new Area would be

A = 2 × (√3 × 4)

A = √3 × 8

The new side length s will be

(√3 / 4) × s² = √3 × 8

s² = 32

s = √32

s = 4√2

The side length increased from 4 to 4√2. That is a 40% increase in side length of the triangle