A distillate flows into an empty 64-gallon drum at spout A and out of the drum at spout B

A distillate flows into an empty 64-gallon drum at spout A and out of the drum at spout B. If the rate of flow through A is 2 gallons per hour, how many gallons per hour must flow out at spout B so that the drum is full in exactly 96 hours?

A) 3/8
B) 1/2
C) 2/3
D) 4/3
E) 8/3

Answer: D

I solved this by saying at its current rate, it will take 32 hours to fill this drum. But I want it to take 96 hours, so I’d like my speed to be 1/3 as fast.

So I want Unit B to “take away” 2/3 of the amount each time Unit A does one unit of work. 2-(2/3) = 4/3.

I got the correct answer but I am thinking algebra might be a better way to go about these questions. I watched Greg’s explanation on this but don’t understand how to approach doing algebra with two different rates. Can anyone clarify this process for me? Thanks

The approach in such questions where there is both inward and outward flow is to add and subtract the rates. Inward flow would get a positive sign whereas outward flow gets a negative sign.
W = R*T
64 = (2-x)*96
x=4/3

Wow, you made that convoluted problem look very simple. Thank you! :smile:

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