Alternate way to solve Greg's hard problem


I did understand Greg’s method. But I’m going wrong on adding the combinations for 1 selection(4C1), 2 combinations(4C2), 3 combinations(4C3) and 4 combinations(4C4). Can you please help how to go about this method ? Also, can you please tell me when exactly the Yes/No type formula to be used ?

You can use it here. Hint: you can either use a particular condiment or not use it.