Let’s say √y^2= 8. Can the y be both -8 and +8?
Because I remember something about how ETS don’t consider the negative number regarding square roots. So if its x^2 = 9 then only 3 would be accepted as x not the -3.
Is what Im remembering correct?
Any correction or opinion would be appreciated. Thank you.
which has two solutions.
However: \sqrt{9} = 3, not \pm 3.
Could you please elaborate further on why the two examples have different solutions?
Try putting a negative number on y^2. It becomes positive.
However: y = \sqrt{x} is a function, and a function can have only one x value for a given y-value (otherwise it isn’t a function).