There are 6 triangles with equal area (in bigger parallelogram ) out of which 2 are from shorter triangle

So I guess it should be 2/6 => 1/3 not sure can you check and confirm once

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yes, that was the correct answer.

thanks for your support!

To be sure you can reason it as 2 triangles having the same height but one have 1/3 base.

let base = 3

Area Triangle Small / Area triangle Big = 1/3

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Area of parallelogram = (1/2) x diagonal1 x diagonal 2

one diagonal is common between the two, other is (1/3rd) then the ratio 1:3

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