Anyone can solve this using algebra?

Cross multiply and simplify.

You’ll get \frac{1}{(n+2)(n+1)} as Qa and \frac{1}{n(n+1)} as Qb. Further (n+1) is common in both so you can ignore it. Finally the comparison will be between \frac{1}{n+2} and \frac{1}{n}. Plug in a few values (except -2,-1 and 0) and there you go!

I got till Qty a is 1/n+2 and Qty B is 1/n. For which value of n will Qty a be greater than qty b here?

Just try a positive and a negative value… say ±3

If n=3 or n= -3 in both cases, Qty B is greater. I am not able to find a value of n where Qty A is greater

Oh okay, sorry. The value where it changes is say at -1.5 or -0.5

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