Can someone please help me with the question posted below?
Instead of doing (1/3)^6 as the solution suggests, I looked at the case of having 6 5s and 6 6s. The probability of each case is (1/6)^(6). I then added the two values together. The solution is prepswift is a little different. Although the answer ends up being similar, I want to know why my method is wrong.
Thank you!
You can have a mix of 5s and 6s.
If 5s and 6s occur at most 5 times, then what we don’t want is for a 5 or a 6 to occur 6 times. The probability of a 5 occuring 6 times is (1/6)^6. The same applies to the probability of a 6 occuring 6 times. Am I coming at this the wrong way?
Thank you
There are only two cases considered in your approach - 555555 and 666666. The question is not asking “what is the probability of getting a number 5 or 6 six times”. In fact: something like “555552” would also work, since the number(s) greater than 4 occur at most five times.
I think I understand. I totally forgot to consider the other cases of having something like 555556 or 666665.
Thank you for the help!
