I always have a lot of doubt about solving number line questions like this. Would be super grateful for any help provided when approaching something like this problem.
Thanks!
Given → PQ = 13 and x - y = 1 or x = 1+y
From the question we can see that PQ is made up of 3x + 2 y = 13
Substituting x = 1+y:
3(1+y) +2y =13\\
3+3y+2y=13\\
5y=10\\
\bf{y=2}
Now, substituting y = 2 in x-y =1
x-y=1\\
x-2=1\\
x=3
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