Hi, I had a question about this problem:

Isn’t the answer to this problem

`1-(365*364*363*362)/(365^4)?`

The probability that no one shares a birthday is `(365*364*363*362)/(365^4)`

, so the answer is 1 minus that.

The solution here overcounts the cases where three or four people share a birthday. The actual difference is small (it’s still approximately 1.63%) but I’m pretty sure the methodology is wrong