Hi, I had a question about this problem:
Isn’t the answer to this problem
1-(365*364*363*362)/(365^4)?
The probability that no one shares a birthday is (365*364*363*362)/(365^4)
, so the answer is 1 minus that.
The solution here overcounts the cases where three or four people share a birthday. The actual difference is small (it’s still approximately 1.63%) but I’m pretty sure the methodology is wrong