The solution looks like easy but I’m really losing my mind solving it or I’m stupid
According to chatgpt,we have to choose those options which are divisible to 2 and 3 and at the same time doesn’t go up 16. So to save time, I only chose 6 and 12 but got chose 10,4 for m and 6,12 for c . My confusion is why it is choosing different options for both subjects? Shouldn’t the chosen numbers be the same? What is the problem in taking same numbers like 6,12 for both C and M??
I hope,I’ve made my problems clear.
I googled the question so i can see what you’re referring to.
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Anyways, i think you have a misunderstanding here.
Let: \frac 12 M = \text{used}_1 and \frac 23C = \text{used}_2
Thus: \text{used}_{\text{total}} = \text{used}_1 + \text{used}_2 = \frac 12 M + \frac 23 C
The answer choices given are referring to the value of \textbf{used}_{\textbf{total}} and not the values of M and C (like you’ve used).
For example, if we consider option C as the \textbf{used}_{\textbf{total}}, then we’d have: \textbf{used}_{\textbf{total}} = 6 = \frac 12M + \frac 23 C
We also have the constraint: M + C = 16, thus solving both gives us M = 28 and C = -12, which makes no sense so C doesn’t work.
But i don’t understand what’s difficult to understand? I didn’t even ask a question though… i’m asking what you wrote if you look at the annotated image.
Okay so you had \text{used}_{\text{total}} = \frac 12 M + \frac 23 C, and you can substitute the value of C from M + C = 16 to get an expression for \text{used}_{\text{total}} solely in terms of M.
After that, you can quickly verify which answer works by considering the bounds on M:
bdw, thanks I will give it a shot once again