area of square = 16 , so length of side = 4
square is centered at 0,0 so the coordinates of square should be (-2,2) (2,2) (2,-2) (-2,-2)
now f(x) = kx2
it is given that k is positive and x2 will always be positive as it is a square
Therefore f(x) should always be positive
So f(x) can only intersect (-2,2) or (2,2) because the y coordinate is positive.
now put (-2,2) in the equation
2 = k * (-2)2
k = 1/2 = 0.5
you can also try for (2,2)
2 = k * (2)2
k = 0.5
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