Answer is C
what is wrong in my method:
Non Blue balls: 6
Blue balls : 4
probability of selecting blue third= P(non-blue) x P(non-blue) x P(blue) = (6/10) x (5/9) x (4/8) = 1/6
Do the first two have to be non-blue?
it cant be blue so possible is:
Red Red
Red Green
Green Red
Green Green
OR
Non blue , Non blue
atleast thats how i am thinking
Where does it say this?
F***!
Thank you a ton!