Divisor and remainder

Mizan · September 22, 2022, 4:04pm

Capture

Can anyone help to solve this?

user4173 · September 22, 2022, 4:43pm

is the ans A

user6469 · September 22, 2022, 4:47pm

Hi Mizan,

If we find the least common multiple (LCM) of 2, 4, 6, and 8, then I think that x = (LCM) + 1 should be the smallest possible x . The LCM in this case is 24. So, I think x is at least 25. (Answer: A)