Hello everyone!
This is question 2 from Graphing Absolute Value Equations Exercise. I had got this problem right. But I need to know if my method was correct.
For this question what I did was:
For option A & C are eliminated as they are not even quadratic equation.
For option B, I asked, Can inside expression be -ve?
i) So when x=0 inside expression is -ve
ii) Therefore 2 cases are possible
For option D, I asked can inside expression be -ve?
i) Inside expression can never be -ve
ii) Therefore no inverted parabola is possible.
iii) Because of which “W”shape isn’t possible.
For option E, I asked can inside expression be -ve?
i) Since -ve case is not possible we won’t have an inverted parabola.
ii) Therefore only 1 case only.
iii) Therefore no “W” shape graph is possible.
For option F, I asked can inside expression be -ve?
i) Since -ve case is not possible we won’t have an inverted parabola.
ii) Therefore only 1 case only.
iii) Therefore no “W” shape graph is possible.
For option G, I asked can inside expression be -ve?
So, no -ve case is possible. Therefore “W” shape is not possible as we don’t get an inverted parabola.
For option H, I asked can inside expression be -ve?
No -ve case is possible. Therefore only 1 case. Therefore “W” shape is not possible as we don’t have an inverted shape parabola.