Doubt: (Refer below for the question) I didn’t understand why 0 was not considered as an integer here. If we take 0 into account, the the numbers would be as follows: 0,1,2,3,104. Since 104 was not in the answer choices, and 106 was not feasible, i chose 100.
Question:
If the average of 5 distinct positive integers is 22, what is the largest that any of them could be?
12
18
100
106
110
EXPLANATION
From the Average Law, we can see that the sum of the 5 integers must be 5 x 22 = 110. Now, in order to maximize the largest of the integers, we must minimize the rest of them. However, we are constrained by the fact that all 5 integers have to be positive and distinct. Thus, the smallest values that the remaining four integers can have are 1, 2, 3 and 4, which add up to 10. This leaves 110 – 10 = 100 as the maximum possible value of the largest integer.
The correct answer is C.