**Doubt:** (Refer below for the question) I didn’t understand why 0 was not considered as an integer here. If we take 0 into account, the the numbers would be as follows: 0,1,2,3,104. Since 104 was not in the answer choices, and 106 was not feasible, i chose 100.

**Question:**

If the average of 5 distinct positive integers is 22, what is the largest that any of them could be?

12

18

100

106

110

*EXPLANATION*

*From the Average Law, we can see that the sum of the 5 integers must be 5 x 22 = 110. Now, in order to maximize the largest of the integers, we must minimize the rest of them. However, we are constrained by the fact that all 5 integers have to be positive and distinct. Thus, the smallest values that the remaining four integers can have are 1, 2, 3 and 4, which add up to 10. This leaves 110 – 10 = 100 as the maximum possible value of the largest integer.*

*The correct answer is C.*