Shud I cross multiply for this question?

How to solve this problem without a calci

whats the relation between x x^2 x^1/2

and 1/x , 1/x^2 and 1/x^3

The square root and the cube root of a negative no does not exist right

Shud I cross multiply for this question?

How to solve this problem without a calci

whats the relation between x x^2 x^1/2

and 1/x , 1/x^2 and 1/x^3

The square root and the cube root of a negative no does not exist right

- I donβt see what cross multiplication has to do with this one
- Estimate: \sqrt{403} \approx 20 and (0.998)^2 \approx 1.
- Elimination looks like a good way for this one. Also: for z, write 1 as a square and use a^2 - b^2 = (a + b)(a - b)
- The square root of a negative number is not real. The cube root of a negative number does indeed exist in the real space though (for example, the cube root of -8 is -2).

**1.** For the first one I did

Initial case :

x --------> 10mins ---------> 2x 10^4 -------> 10 mins -----------> 2 x 10^x

as per the question

10^4 ------> 60 mins ----. ?

2^6x 10^4

so then the ans is C is it correct

**2.**

60 x 1^2

------------- = 3

20

Is my answer correct?

Yes

thanks

**4**. Oh yes I assumed that the cube root does not exist

so the answer is between -4 and -5 thats C

**3**

I didnt follow the 3rd one

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Yes for Q4

For Q3, notice that z is negative (as (1 - 0.08)^2 < 1). Also, y > x as (0.008)^{2} < 1. Hence, the relation is z < x < y β option C

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Thanks a lot