I didnâ€™t quite understand what exactly was the question asking us to find but here is what I thought it did :

From the question we get : t^2 = h^2 + b^2 â€”(Pythagoras Theorem )

from this option A will always be 1. So for all the values of w^2 and x^2 this expression will remain the same

One more way to look at it, using trigonometry identities

Assuming angle a between b and t.

cos(a)=h/t

sin(a)=b/t

tan(a)=h/b

Hence correct answer is A

cos^2(a)+sin^2(a)=1 ; For any values of b,t,h

basically, this question can be sloved by that cos ^2+sin ^2=1, where cos =x,sin =w

the value of A is always 1

t^2 = h^2+b^2

Therefore, 1= (h^2+b^2)/t^2

A. w^2 + x^2 = (h^2+b^2)/t^2 = 1

this equation shows â€ś(h^2+b^2)/t^2 = 1â€ť, whatever the value of t,h,b is- the answer will always be 1

Therefore, A is correct

Iâ€™m thinking of ( t^2=h^2+b^2) could t^2 be divided by the whole equation ? isnâ€™t it

H^2+b^2-t^2=0 if we want to take it to the other side ?

Or we can do both ?

Its better to divide t^2 on both sides because then we directly get option a. We can do the other thing too but that wont return us any result