Factors and Circles

GRE Quant Problem Solving
1

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I used the brute force method but I found it to be too time consuming

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What I did here is I found the powers of 2 in series
like
1
2
4
…
1024
then found out which value of 2s power’s would give 960
I got 1024-64 = 960
So the answer is 3 for quantity A. Is it right?
Is there any other method?
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Did anyone solve this sum another way coz the idea of drawing a perpendicular and then how to consider the 30 & 60 degree angles is something that I didnt follow

2

Q2.

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The answer is 4 for x-y with the same method (You probably made a silly mistake) but that is still less than B so QuantB is greater,

Q3

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(Sorry for the shitty drawing)
angle Y will be 60 as Angle X will be 90(Do check Greg’s lecture)
Radius YC = Radius XC which gives the same angle as 60 which makes this whole structure an equilateral
The area of the Triangle is (root3)/4 x side^2
and the area of the sector is pie x radius^2*(angle/360)

1 Like
3

You are right I made a silly mistake.
Np the drawing is understandable Thank you so much for your efforts