I edited the source for you this time but please mention the source of question from next time.

AB = AE = lets say 2

Now join BD and CF, so, point where CF meet on BD = X

You will get 4 rt tringles in Quad. BCDF

Area of ABE = \frac{b\times h}{2}=\frac{4}{2}=2

Area of one of the rt. triangles of Quad. BCDF = \frac{b\times h}{2}=\frac{1}{2} and we got 4 of them so, 4 \times \frac{1}{2}=2

Ans C

Thanks for adding the source of the question. I will take care of it going forward.

Could you please explain how AB = AE?

Side opposite to equal angle are equal