IN A FIGURE LIKE THIS CAN WE ASSUME A EQUALATERAL TRAINGLE CUT INTO 6 CONGURENT TRAINGLES EACH TRAINGLE WILL HAVE SAME AREA THEREFORE, I GOT 2/12 -->> 1/6 AS THE CORRRECT ANSWER **DID I GET LUCKEY ??**

You’re absolutely right! Try applying some properties of parallelograms or triangles to just make sure you didn’t get lucky

yes ! i checked it using 30-60-90 and it was all fine and dandy

The 6 triangles are congruent since the equilateral triangle has been bisected by 90 degrees in each case.